What is the value of x in left(4^{x}right)^{3}=4^{36} ?

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Accepted Answer

Step:1 ：Given the equation: (left(4^{x}right)^{3}=4^{36})Step:2 ：Using the property of exponents: ((a^m)^n = a^{mn}), we get: (4^{3x} = 4^{36})Step:3 ：Since the bases are equal, we can equate the exponents: (3x = 36)Step:4 ：Divide both sides by 3: (x = frac{36}{3})Step:5 ：Simplify: (x = 12)Step:6 ：Final Answer: (boxed{12})

Answer

Step: 1 ：Given the equation: (left(4^{x}right)^{3}=4^{36})Step: 2 ：Using the property of exponents: ((a^m)^n = a^{mn}), we get: (4^{3x} = 4^{36})Step: 3 ：Since the bases are equal, we can equate the exponents: (3x = 36)Step: 4 ：Divide both sides by 3: (x = frac{36}{3})Step: 5 ：Simplify: (x = 12)Step: 6 ：Final Answer: (boxed{12})

What is the value of $x$ in $\left(4^{x}\right)^{3}=4^{36} ?$

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