A copper statue has a volume of $35 \mathrm{~cm}^{3}$ and a mass of $312.9 \mathrm{~g}$.
Work out the density of the statue.
Give your answer to 2 d.p.

Answer

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Answer

$\boxed{\rho = 8.94 \mathrm{~g/cm}^{3}}$

Steps

Step 1 ：Given the mass of the copper statue as $m = 312.9 \mathrm{~g}$ and the volume as $V = 35 \mathrm{~cm}^{3}$.

Step 2 ：Use the formula for density: $\rho = \frac{m}{V}$.

Step 3 ：Plug in the given values: $\rho = \frac{312.9}{35}$.

Step 4 ：Calculate the density: $\rho = 8.94 \mathrm{~g/cm}^{3}$.

Step 5 ：$\boxed{\rho = 8.94 \mathrm{~g/cm}^{3}}$