Determine the equation of the circle with radius ( sqrt{120} ) and center ( (-5,-2) ).

Question

Accepted Answer

Step:1 ：1. Write the general equation of a circle: (x-a)^2 + (y-b)^2 = r^2Step:2 ：2. Plug in the center (-5,-2) and radius ( sqrt{120} ): (x+5)^2 + (y+2)^2 = ( sqrt{120} )^2Step:3 ：3. Simplify the equation: (x+5)^2 + (y+2)^2 = 120

Answer

Step: 1 ：1. Write the general equation of a circle: (x-a)^2 + (y-b)^2 = r^2Step: 2 ：2. Plug in the center (-5,-2) and radius ( sqrt{120} ): (x+5)^2 + (y+2)^2 = ( sqrt{120} )^2Step: 3 ：3. Simplify the equation: (x+5)^2 + (y+2)^2 = 120

Determine the equation of the circle with radius $\sqrt{120}$ and center $(- 5, - 2)$ .

Answer

Popular Problems

Determine the equation of the circle with radius 120 and center (−5,−2).

Answer

Popular Problems

Determine the equation of the circle with radius $\sqrt{120}$ and center $(- 5, - 2)$ .