Let $f (x, y) = 2^{x} + 9 x y$ , find $f (0, - 3), f (- 3, 2)$ , and $f (3, 2)$ .
$f (0, - 3) = ◻$ (Simplify your answer.)
$f (- 3, 2) = ◻$ (Simplify your answer.)
$f (3, 2) = ◻$ (Simplify your answer.)

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Answer

So, the final answers are $f (0, - 3) = 1$ , $f (- 3, 2) = - 53.875$ , and $f (3, 2) = 62$ .

Steps

Step 1 ：Given the function $f (x, y) = 2^{x} + 9 x y$ , we are asked to find the values of $f (0, - 3)$ , $f (- 3, 2)$ , and $f (3, 2)$ .

Step 2 ：To find these values, we substitute the given x and y values into the function and simplify.

Step 3 ：For $f (0, - 3)$ , we substitute $x = 0$ and $y = - 3$ into the function to get $2^{0} + 9 * 0 * (- 3)$ , which simplifies to 1.

Step 4 ：For $f (- 3, 2)$ , we substitute $x = - 3$ and $y = 2$ into the function to get $2^{- 3} + 9 * (- 3) * 2$ , which simplifies to -53.875.

Step 5 ：For $f (3, 2)$ , we substitute $x = 3$ and $y = 2$ into the function to get $2^{3} + 9 * 3 * 2$ , which simplifies to 62.

Step 6 ：So, the final answers are $f (0, - 3) = 1$ , $f (- 3, 2) = - 53.875$ , and $f (3, 2) = 62$ .