Let $f(x, y)=2^{x}+8 x y$, find $f(0,-3), f(-3,2)$, and $f(3,2)$.
$f(0,-3)=\square$ (Simplify your answer. $)$

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Answer

Final Answer: $\boxed{1}$

Steps

Step 1 ：Let's substitute $x=0$ and $y=-3$ into the function $f(x, y)=2^{x}+8 x y$.

Step 2 ：After substituting, we get $f(0,-3)=2^{0}+8*0*(-3)$.

Step 3 ：Simplifying the expression, we get $f(0,-3)=1+0$.

Step 4 ：So, $f(0,-3)=1$.

Step 5 ：Final Answer: $\boxed{1}$