Use the data in the following table, which lists drive-thru order accuracy at popular fast food chains. Assume that orders are randomly selected from those included in the table.
Drive-thru Restaurant
\begin{tabular}{|l|c|c|c|c|}
\hline & A & B & C & D \\
\hline Order Accurate & 316 & 272 & 249 & 146 \\
\hline Order Not Accurate & 34 & 57 & 39 & 12 \\
\hline
\end{tabular}
If three different orders are selected, find the probability that they are all from Restaurant D.
The probability is
(Round to four decimal places as needed.)

Step 1 ：First, calculate the total number of orders by adding all the orders from each restaurant. This gives us a total of 1125 orders.

Step 2 ：Next, find the number of orders from Restaurant D, which is 158.

Step 3 ：Then, calculate the probability of an order being from Restaurant D by dividing the number of orders from Restaurant D by the total number of orders. This gives us a probability of \(\frac{158}{1125} \approx 0.1404\).

Step 4 ：Since we are selecting three orders, and we want all of them to be from Restaurant D, we need to multiply the probability of one order being from Restaurant D by itself three times. This gives us a probability of \(0.1404 \times 0.1404 \times 0.1404 \approx 0.0028\).

Step 5 ：Final Answer: The probability that all three orders are from Restaurant D is approximately \(\boxed{0.0028}\).