Write the equation of the line that passes through the points (-6,-1) and (-4,2). Put your answer in fully simplified point-slope form, unless it is a vertical or horizontal line.

Step 1 ：First, we need to find the slope of the line. The slope of a line passing through two points $(x1,y1)$ and $(x2,y2)$ is given by the formula $m=\frac{(y2-y1)}{(x2-x1)}$.

Step 2 ：Substitute the given points (-6,-1) and (-4,2) into the formula to find the slope: $m=\frac{(2--1)}{(-4--6)}=1.5$.

Step 3 ：Next, we use the point-slope form of a line, which is $y-y1=m(x-x1)$, where m is the slope of the line and $(x1,y1)$ is a point on the line.

Step 4 ：Substitute the slope and one of the points into the point-slope form to find the equation of the line: $y--1=1.5(x--6)$.

Step 5 ：Simplify the equation by removing the double negatives and simplifying the right side of the equation: $y+1=1.5x+9$.

Step 6 ：Final Answer: The equation of the line in fully simplified point-slope form is $\boxed{{\displaystyle y+1=1.5x+9}}$.