( lim _{x rightarrow 0} frac{sin 2 x}{5 x} )

Question

Accepted Answer

Step:1 ：( lim _{x rightarrow 0} frac{sin 2 x}{5 x} = frac{1}{5} lim _{x rightarrow 0} frac{sin 2 x}{2 x} )Step:2 ：( lim _{x rightarrow 0} frac{sin 2 x}{2 x} = lim _{x rightarrow 0} frac{sin 2 x}{2 x} cdot frac{2}{sin 2 x} )Step:3 ：( frac{1}{5} lim _{x rightarrow 0} frac{sin 2 x}{2 x} = frac{1}{5} cdot 1 )

Answer

Step: 1 ：( lim _{x rightarrow 0} frac{sin 2 x}{5 x} = frac{1}{5} lim _{x rightarrow 0} frac{sin 2 x}{2 x} )Step: 2 ：( lim _{x rightarrow 0} frac{sin 2 x}{2 x} = lim _{x rightarrow 0} frac{sin 2 x}{2 x} cdot frac{2}{sin 2 x} )Step: 3 ：( frac{1}{5} lim _{x rightarrow 0} frac{sin 2 x}{2 x} = frac{1}{5} cdot 1 )

$lim_{x \to 0} \frac{\sin 2 x}{5 x}$

Answer

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Answer

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$lim_{x \to 0} \frac{\sin 2 x}{5 x}$