Problem

8. The pressure of a constant amount of gas at a constant temperature is incriased from \( 3.1 \mathrm{~atm} \) to \( 4300 \mathrm{mmHg} \). What is its volume if it was initially \( 2.3 \mathrm{~L} \) ?

Answer

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Answer

\( V_2 = \frac{P_1V_1}{P_2} \)

Steps

Step 1 :\( P_1 = 3.1 \mathrm{~atm} \), \( P_2 = 4300 \mathrm{~mmHg} \), \( V_1 = 2.3 \mathrm{~L} \)

Step 2 :\( P_1V_1 = P_2V_2 \)

Step 3 :\( V_2 = \frac{P_1V_1}{P_2} \)

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