A gas held in a sealed container has a pressure of 2.6 atm. If the volume is raised from ( 820 mathrm{~mL} ) to ( 2.1 mathrm{~L} ), then what is the new pressure of in millimeters of mercury?

Question

Accepted Answer

Step:1 ：P1 * V1 = P2 * V2Step:2 ：(2.6mathrm{~atm} * 820mathrm{~mL} = P2 * 2.1mathrm{~L})Step:3 ：(P2 = frac{2.6mathrm{~atm} * 820mathrm{~mL}}{2.1mathrm{~L}} * frac{760mathrm{~mmHg}}{1mathrm{~atm}})

Answer

Step: 1 ：P1 * V1 = P2 * V2Step: 2 ：(2.6mathrm{~atm} * 820mathrm{~mL} = P2 * 2.1mathrm{~L})Step: 3 ：(P2 = frac{2.6mathrm{~atm} * 820mathrm{~mL}}{2.1mathrm{~L}} * frac{760mathrm{~mmHg}}{1mathrm{~atm}})

A gas held in a sealed container has a pressure of 2.6 atm. If the volume is raised from $820 mL$ to $2.1 L$ , then what is the new pressure of in millimeters of mercury?

Answer

Popular Problems

A gas held in a sealed container has a pressure of 2.6 atm. If the volume is raised from 820 mL to 2.1 L, then what is the new pressure of in millimeters of mercury?

Answer

Popular Problems

A gas held in a sealed container has a pressure of 2.6 atm. If the volume is raised from $820 mL$ to $2.1 L$ , then what is the new pressure of in millimeters of mercury?