Problem

A gas held in a sealed container has a pressure of 2.6 atm. If the volume is raised from \( 820 \mathrm{~mL} \) to \( 2.1 \mathrm{~L} \), then what is the new pressure of in millimeters of mercury?

Answer

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Answer

\(P2 = \frac{2.6\mathrm{~atm} * 820\mathrm{~mL}}{2.1\mathrm{~L}} * \frac{760\mathrm{~mmHg}}{1\mathrm{~atm}}\)

Steps

Step 1 ：P1 * V1 = P2 * V2

Step 2 ：\(2.6\mathrm{~atm} * 820\mathrm{~mL} = P2 * 2.1\mathrm{~L}\)

Step 3 ：\(P2 = \frac{2.6\mathrm{~atm} * 820\mathrm{~mL}}{2.1\mathrm{~L}} * \frac{760\mathrm{~mmHg}}{1\mathrm{~atm}}\)

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