Problem

Find the cube root of
\[
-27
\]
that graphs in the first quadrant.
\[
3\left(\cos [?]^{\circ}+i \sin [?]^{\circ}\right)
\]

Answer

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Answer

\(z = 3(\cos[60^\circ] + i\sin[60^\circ])\)

Steps

Step 1 :\(z^3 = -27\)

Step 2 :\(z = -3(\cos[180^\circ] + i\sin[180^\circ])\)

Step 3 :\(z = 3(\cos[60^\circ] + i\sin[60^\circ])\)

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