\( 2 y^{\prime \prime}+4 y^{\prime}+2 y=0 \)
Answer
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Answer
\(y=c_1 e^{-x}+c_2 xe^{-x}\)
Steps
Step 1 ：\(y= e^{rx}\)
Step 2 ：\( r^2+2r+1=0\)
Step 3 ：\(y=c_1 e^{-x}+c_2 xe^{-x}\)
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