Solve the equation for the variable y:
$25 y^{2}-49$
The solutions to the equation are \(y = \boxed{-\frac{7}{5}}\) and \(y = \boxed{\frac{7}{5}}\).
Step 1 :The given equation is a difference of squares, which can be factored as \((5y)^2 - (7)^2\).
Step 2 :The difference of squares can be factored as \((a-b)(a+b)\), where \(a = 5y\) and \(b = 7\).
Step 3 :After factoring, we can solve for \(y\) by setting each factor equal to zero.
Step 4 :The solutions to the equation are \(y = \boxed{-\frac{7}{5}}\) and \(y = \boxed{\frac{7}{5}}\).