What is an equation of the line that passes through the points $(6,3)$ and $(-6,1)$ ?
Answer
Final Answer: The equation of the line that passes through the points $(6,3)$ and $(-6,1)$ is $\boxed{y = 0.1667x + 2}$
Step 1 ：Find the slope of the line using the formula: $m = \frac{y_2 - y_1}{x_2 - x_1}$
Step 2 ：Calculate the slope: $m = \frac{1 - 3}{-6 - 6} = \frac{-2}{-12} = \frac{1}{6} = 0.1667$
Step 3 ：Use the point-slope form of a linear equation to find the equation of the line: $y - y_1 = m(x - x_1)$
Step 4 ：Substitute the slope and one of the points into the equation: $y - 3 = 0.1667(x - 6)$
Step 5 ：Simplify the equation: $y = 0.1667x + 2$
Step 6 ：Final Answer: The equation of the line that passes through the points $(6,3)$ and $(-6,1)$ is $\boxed{y = 0.1667x + 2}$
