Part 1 of 2
Points: 0 of 2
The number of cells in a tumor doubles every 4.5 months. If the tumor begins with a single cell, how many cells will there be after 2 years? after 5 years?

How may cells will there be after 2 years?
(Do not round until the final answer. Then round to the nearest whole number as needed)

Step 1 ：Given that the number of cells in a tumor doubles every 4.5 months, we can model this as an exponential growth problem. The formula for exponential growth is \(A = P * (1 + r/n)^{nt}\), where:

Step 2 ：\(A\) is the final amount of cells after \(n\) years.

Step 3 ：\(P\) is the initial amount of cells (in this case, 1).

Step 4 ：\(r\) is the growth rate (in this case, 100% or 1 in decimal form).

Step 5 ：\(n\) is the number of times the cells double per year (in this case, 12/4.5 = 2.67 times).

Step 6 ：\(t\) is the time the cells are growing for in years (in this case, 2 years).

Step 7 ：Substituting these values into the formula, we get \(A = 1 * (1 + 1/2.67)^{2.67*2}\).

Step 8 ：Calculating this gives \(A = 5.465304833469831\).

Step 9 ：Rounding this to the nearest whole number, we get \(A = 5\).

Step 10 ：Final Answer: There will be \(\boxed{5}\) cells after 2 years.