$\log \left(x^{2}-7 x+11\right)< 0$
\(\boxed{2 < x < 5}\)
Step 1 :Rewrite the inequality as: \(x^2 - 7x + 10 < 0\)
Step 2 :Find the roots of the quadratic equation: \(x^2 - 7x + 10 = 0\)
Step 3 :Use the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) where a = 1, b = -7, and c = 10
Step 4 :Calculate the roots: \(x_1 = 2.0\) and \(x_2 = 5.0\)
Step 5 :Since the inequality is less than 0, find the interval between the roots where the inequality holds true
Step 6 :\(\boxed{2 < x < 5}\)