If logCA=1.214 and logCB=1.415, what is the value of logc(B2A), to the nearest hundredth?Answer:
Find the final answer: 1.62
Step 1 :Rewrite the expression using properties of logarithms: logC(B2A)=logCB2−logCA
Step 2 :Substitute the given values: logC(B2A)=(2×1.415)−1.214
Step 3 :Calculate the value: logC(B2A)=2.83−1.214
Step 4 :Find the final answer: 1.62