Problem

If logCA=1.214 and logCB=1.415, what is the value of logc(B2A), to the nearest hundredth?
Answer:

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Answer

Find the final answer: 1.62

Steps

Step 1 :Rewrite the expression using properties of logarithms: logC(B2A)=logCB2logCA

Step 2 :Substitute the given values: logC(B2A)=(2×1.415)1.214

Step 3 :Calculate the value: logC(B2A)=2.831.214

Step 4 :Find the final answer: 1.62

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