Find the common ratio and write out the first four terms of the geometric sequence $\frac{2^{n - 3}}{6}$

Common ratio is
$a_{1} = ◻, a_{2} = ◻, a_{3} = ◻, a_{4} = ◻$

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$The common ratio is 2 and the first four terms of the geometric sequence are \frac{1}{24}, \frac{1}{12}, \frac{1}{6}, and \frac{1}{3}$

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Step 1 ：The common ratio of a geometric sequence is the ratio between any term and the previous term. In this case, the common ratio is 2, because each term is multiplied by 2 to get the next term.

Step 2 ：The first four terms can be found by substituting n=1, n=2, n=3, and n=4 into the formula for the nth term.

Step 3 ：Let's calculate these values. For n=1, $a_{1} = \frac{2^{1 - 3}}{6} = \frac{1}{24}$ . For n=2, $a_{2} = \frac{2^{2 - 3}}{6} = \frac{1}{12}$ . For n=3, $a_{3} = \frac{2^{3 - 3}}{6} = \frac{1}{6}$ . For n=4, $a_{4} = \frac{2^{4 - 3}}{6} = \frac{1}{3}$ .

Step 4 ： $The common ratio is 2 and the first four terms of the geometric sequence are \frac{1}{24}, \frac{1}{12}, \frac{1}{6}, and \frac{1}{3}$

Find the common ratio and write out the first four terms of the geometric sequence 2n−36 Common ratio isa1=◻,a2=◻,a3=◻,a4=◻ Question Help: ◻ Message instructorSubmit Question

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Find the common ratio and write out the first four terms of the geometric sequence $\frac{2^{n - 3}}{6}$

Common ratio is
$a_{1} = ◻, a_{2} = ◻, a_{3} = ◻, a_{4} = ◻$

Question Help: $◻$ Message instructor
Submit Question