Factor.
\[
d^{2}-8 d+16
\]

Answer

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Answer

So, the factored form of \(d^2 - 8d + 16\) is \(\boxed{(d - 4)^2}\).

Steps

Step 1 ：The given expression is a quadratic expression of the form \(ax^2 + bx + c\).

Step 2 ：To factorize it, we need to find two numbers that add up to -8 (the coefficient of d) and multiply to 16 (the constant term).

Step 3 ：The numbers that satisfy these conditions are -4 and -4 because -4 + -4 = -8 and -4 * -4 = 16.

Step 4 ：So, the factorization of the given expression is: \(d^2 - 8d + 16 = (d - 4)(d - 4)\).

Step 5 ：So, the factored form of \(d^2 - 8d + 16\) is \(\boxed{(d - 4)^2}\).