Problem

Differentiate the function.
\[
\begin{array}{l}
F(s)=\ln (\ln (9 s)) \\
F^{\prime}(s)=
\end{array}
\]

Answer

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Answer

\(\boxed{F'(s) = \frac{1}{s \ln(9s)}}\) is the final answer.

Steps

Step 1 :The problem is asking for the derivative of the function \(F(s) = \ln(\ln(9s))\).

Step 2 :To solve this, we can use the chain rule of differentiation. The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function.

Step 3 :In this case, the outer function is \(\ln(x)\) and the inner function is \(\ln(9s)\).

Step 4 :Applying the chain rule, we get \(F'(s) = \frac{1}{s \ln(9s)}\).

Step 5 :\(\boxed{F'(s) = \frac{1}{s \ln(9s)}}\) is the final answer.

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