Solve for $x$
\[
\log _{2}(x+6)=\log _{2}(x+3)+2
\]
If there is more than one solution, separate them with commas. If there is no solution, click on "No solution".
\[
x=
\]
Answer
Final Answer: \(\boxed{\text{No solution}}\)
Step 1 ：The equation given is \(\log _{2}(x+6)=\log _{2}(x+3)+2\)
Step 2 ：Since the equation involves logarithms with the same base, we can use the property of logarithms that states if \(\log_b{a} = \log_b{c}\), then \(a = c\). Therefore, we can set the arguments of the logarithms equal to each other and solve for \(x\).
Step 3 ：However, when we do this, we get \(x = x\), which is not a valid equation.
Step 4 ：This means that the solution set is empty, and there is no real number solution for the equation.
Step 5 ：Final Answer: \(\boxed{\text{No solution}}\)
