sum_{i=1}^{10}left[1+(-1)^{i}right]=

Question

Accepted Answer

Step:1 ：The sum is over the range from 1 to 10. For each i, the term is (1+(-1)^{i}). When i is even, ((-1)^{i}) is 1, and when i is odd, ((-1)^{i}) is -1. So, the term is 2 for even i and 0 for odd i.Step:2 ：Since half of the numbers from 1 to 10 are even, the sum should be (2*5=10).Step:3 ：Final Answer: (boxed{10})

Answer

Step: 1 ：The sum is over the range from 1 to 10. For each i, the term is (1+(-1)^{i}). When i is even, ((-1)^{i}) is 1, and when i is odd, ((-1)^{i}) is -1. So, the term is 2 for even i and 0 for odd i.Step: 2 ：Since half of the numbers from 1 to 10 are even, the sum should be (2*5=10).Step: 3 ：Final Answer: (boxed{10})

$\sum_{i = 1}^{10} [1 + (- 1)^{i}] =$

Answer

Popular Problems

∑i=110[1+(−1)i]=

Answer

Popular Problems

$\sum_{i = 1}^{10} [1 + (- 1)^{i}] =$