1. A ( 0.50 mathrm{~kg} ) football is thrown with a velocity of ( 15 mathrm{~m} / mathrm{s} ) to the right. A stationary receiver catches the ball and brings it to rest in ( 0.020 mathrm{~s} ). What is the force exerted on the ball by the receiver?

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Accepted Answer

Step:1 ：(v = u + at Longrightarrow a = frac{v - u}{t})Step:2 ：(a = frac{0 - 15}{0.020} = -750 mathrm{~m} / mathrm{s}^2)Step:3 ：(F = ma = 0.50 times -750 = -375 mathrm{~N})

Answer

Step: 1 ：(v = u + at Longrightarrow a = frac{v - u}{t})Step: 2 ：(a = frac{0 - 15}{0.020} = -750 mathrm{~m} / mathrm{s}^2)Step: 3 ：(F = ma = 0.50 times -750 = -375 mathrm{~N})

1. A \( 0.50 \mathrm{~kg} \) football is thrown with a velocity of \( 15 \mathrm{~m} / \mathrm{s} \) to the right. A stationary receiver catches the ball and brings it to rest in \( 0.020 \mathrm{~s} \). What is the force exerted on the ball by the receiver?

Answer

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