Problem

1. A 0.50 kg football is thrown with a velocity of 15 m/s to the right. A stationary receiver catches the ball and brings it to rest in 0.020 s. What is the force exerted on the ball by the receiver?

Answer

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Answer

F=ma=0.50×750=375 N

Steps

Step 1 :v=u+ata=vut

Step 2 :a=0150.020=750 m/s2

Step 3 :F=ma=0.50×750=375 N

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