1. A 0.50 kg football is thrown with a velocity of 15 m/s to the right. A stationary receiver catches the ball and brings it to rest in 0.020 s. What is the force exerted on the ball by the receiver?
F=ma=0.50×−750=−375 N
Step 1 :v=u+at⟹a=v−ut
Step 2 :a=0−150.020=−750 m/s2
Step 3 :F=ma=0.50×−750=−375 N