Problem

How high can a \( 40 \mathrm{~N} \) force move a load, when \( 395 \mathrm{~J} \) of work is done?

Answer

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Answer

\(d = \frac{395\mathrm{~J}}{40\mathrm{~N}}\)

Steps

Step 1 ：\(W = Fd\cos(\theta)\)

Step 2 ：\(d = \frac{W}{F}\)

Step 3 ：\(d = \frac{395\mathrm{~J}}{40\mathrm{~N}}\)

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