Problem

The number of tickets purchased by an individual for Beckham College's holiday music festival is a uniformly distributed random variable ranging from 5 to 15 .

Find the mean and standard deviation of this random variable. (Round your answers to 2 decimal places.)
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\hline & \\
\hline Mean & \\
\hline Standard deviation & \\
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\end{tabular}

Answer

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Answer

The mean is \(\boxed{10.0}\) and the standard deviation is \(\boxed{3.16}\).

Steps

Step 1 :The problem is asking for the mean and standard deviation of a uniformly distributed random variable. The formula for the mean of a uniform distribution is \((a+b)/2\), where a and b are the lower and upper bounds of the distribution. The formula for the standard deviation of a uniform distribution is \(\sqrt{(b-a+1)^2 - 1}/12\). In this case, a is 5 and b is 15.

Step 2 :Substitute a = 5 and b = 15 into the formula for the mean: \((5+15)/2 = 10.0\).

Step 3 :Substitute a = 5 and b = 15 into the formula for the standard deviation: \(\sqrt{(15-5+1)^2 - 1}/12 = 3.1622776601683795\).

Step 4 :Round the standard deviation to two decimal places: 3.16.

Step 5 :The mean is \(\boxed{10.0}\) and the standard deviation is \(\boxed{3.16}\).

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