Question 13 of 60
The velocity of water in a pipe is given by $v = \frac{121}{4 + x^{2}}$ , where $x$ is the distance from the center of the pipe. If $v = 9$ centimeters per second, then the value of $x$ , in centimeters, is

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Final Answer: The value of $x$ in centimeters is $\frac{\sqrt{85}}{3}$ .

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Step 1 ：The velocity of water in a pipe is given by $v = \frac{121}{4 + x^{2}}$ , where $x$ is the distance from the center of the pipe. If $v = 9$ centimeters per second, then the value of $x$ , in centimeters, is

Step 2 ：We can solve this by setting the equation $v = \frac{121}{4 + x^{2}}$ equal to 9 and solving for $x$ .

Step 3 ：Solving the equation gives us $x = \pm \frac{\sqrt{85}}{3}$ .

Step 4 ：However, since $x$ represents a distance, it cannot be negative. Therefore, the only valid solution is $x = \frac{\sqrt{85}}{3}$ .

Step 5 ：Final Answer: The value of $x$ in centimeters is $\frac{\sqrt{85}}{3}$ .

Question 13 of 60The velocity of water in a pipe is given by v=1214+x2, where x is the distance from the center of the pipe. If v=9 centimeters per second, then the value of x, in centimeters, is

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Question 13 of 60
The velocity of water in a pipe is given by $v = \frac{121}{4 + x^{2}}$ , where $x$ is the distance from the center of the pipe. If $v = 9$ centimeters per second, then the value of $x$ , in centimeters, is