Question 13 of 60
The velocity of water in a pipe is given by $v=\frac{121}{4+x^{2}}$, where $x$ is the distance from the center of the pipe. If $v=9$ centimeters per second, then the value of $x$, in centimeters, is

Step 1 ：The velocity of water in a pipe is given by \(v=\frac{121}{4+x^{2}}\), where \(x\) is the distance from the center of the pipe. If \(v=9\) centimeters per second, then the value of \(x\), in centimeters, is

Step 2 ：We can solve this by setting the equation \(v=\frac{121}{4+x^{2}}\) equal to 9 and solving for \(x\).

Step 3 ：Solving the equation gives us \(x = \pm \frac{\sqrt{85}}{3}\).

Step 4 ：However, since \(x\) represents a distance, it cannot be negative. Therefore, the only valid solution is \(x = \frac{\sqrt{85}}{3}\).

Step 5 ：Final Answer: The value of \(x\) in centimeters is \(\boxed{\frac{\sqrt{85}}{3}}\).