Solve $e^{2 \mathrm{t}}=1800$ for $\mathrm{t}$.
$t \approx$
(Round to three decimal places as needed.)

Answer

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Answer

Final Answer: $\boxed{3.748}$

Steps

Step 1 ：The given equation is $e^{2t} = 1800$.

Step 2 ：Take the natural logarithm (ln) on both sides of the equation to get $2t = ln(1800)$.

Step 3 ：Isolate t by dividing both sides of the equation by 2 to get $t = \frac{ln(1800)}{2}$.

Step 4 ：Calculate to get $t \approx 3.748$.

Step 5 ：Final Answer: $\boxed{3.748}$