(B)
${\begin{cases} 2 x - 3 y - z = 0 \\ - 2 x + y + 2 z = - 9 \\ 4 x + 2 y + z = 1 \end{cases}$

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Answer

$x = 0.5, y = 2, z = - 5$

Steps

Step 1 ： ${\begin{cases} 2 x - 3 y - z = 0 \\ - 2 x + y + 2 z = - 9 \\ 4 x + 2 y + z = 1 \end{cases}$

Step 2 ：Use matrix operations to solve the system of linear equations.

Step 3 ： $[\begin{matrix} 2 & - 3 & - 1 \\ - 2 & 1 & 2 \\ 4 & 2 & 1 \end{matrix}] [\begin{matrix} x \\ y \\ z \end{matrix}] = [\begin{matrix} 0 \\ - 9 \\ 1 \end{matrix}]$

Step 4 ： $[\begin{matrix} x \\ y \\ z \end{matrix}] = [\begin{matrix} 0.5 \\ 2 \\ - 5 \end{matrix}]$

Step 5 ： $x = 0.5, y = 2, z = - 5$

(B){2x−3y−z=0−2x+y+2z=−94x+2y+z=1

Answer

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(B)
${\begin{cases} 2 x - 3 y - z = 0 \\ - 2 x + y + 2 z = - 9 \\ 4 x + 2 y + z = 1 \end{cases}$