$\begin{array}{l} H_{0} : p = 0.72 \\ H_{1} : p > 0.72 \end{array}$
Your sample consists of 130 subjects, with 91 successes. Calculate the test statistic, rounded to 2 decimal places
$z =$

Answer

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Answer

Final Answer: $- 0.51$

Steps

Step 1 ：Define the null hypothesis $H_{0} : p = 0.72$ and the alternative hypothesis $H_{1} : p > 0.72$ .

Step 2 ：The sample consists of 130 subjects, with 91 successes.

Step 3 ：Calculate the sample proportion $\hat{p}$ by dividing the number of successes by the sample size: $\hat{p} = \frac{91}{130}$ .

Step 4 ：Substitute $\hat{p} = 0.7$ , $p_{0} = 0.72$ , and $n = 130$ into the formula for the test statistic: $z = \frac{\hat{p} - p_{0}}{\sqrt{\frac{p_{0} (1 - p_{0})}{n}}}$ .

Step 5 ：Calculate the test statistic to get $z = - 0.51$ .

Step 6 ：Final Answer: $- 0.51$

H0:p=0.72H1:p>0.72Your sample consists of 130 subjects, with 91 successes. Calculate the test statistic, rounded to 2 decimal placesz=

Answer

Popular Problems

$\begin{array}{l} H_{0} : p = 0.72 \\ H_{1} : p > 0.72 \end{array}$
Your sample consists of 130 subjects, with 91 successes. Calculate the test statistic, rounded to 2 decimal places
$z =$