Find $\int(x+3)(x-7) d x$
The integral of the function \((x+3)(x-7)\) with respect to x is \(\boxed{\frac{x^3}{3} - 2x^2 - 21x + C}\)
Step 1 :Given the integral to solve is \(\int(x+3)(x-7) dx\)
Step 2 :First, we expand the expression inside the integral to get \(x^2 - 4x - 21\)
Step 3 :Then, we integrate term by term to get \(\frac{x^3}{3} - 2x^2 - 21x\)
Step 4 :Finally, we add the constant of integration, C, to get the final answer
Step 5 :The integral of the function \((x+3)(x-7)\) with respect to x is \(\boxed{\frac{x^3}{3} - 2x^2 - 21x + C}\)