Problem

Find $\int(x+3)(x-7) d x$

Answer

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Answer

The integral of the function \((x+3)(x-7)\) with respect to x is \(\boxed{\frac{x^3}{3} - 2x^2 - 21x + C}\)

Steps

Step 1 :Given the integral to solve is \(\int(x+3)(x-7) dx\)

Step 2 :First, we expand the expression inside the integral to get \(x^2 - 4x - 21\)

Step 3 :Then, we integrate term by term to get \(\frac{x^3}{3} - 2x^2 - 21x\)

Step 4 :Finally, we add the constant of integration, C, to get the final answer

Step 5 :The integral of the function \((x+3)(x-7)\) with respect to x is \(\boxed{\frac{x^3}{3} - 2x^2 - 21x + C}\)

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