Problem

What is the equation of the line that passes through the point (5,8) and has a slope of 1 ?

Answer

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Answer

y=x+3 is the equation of the line that passes through the point (5,8) and has a slope of 1.

Steps

Step 1 ：The equation of a line in slope-intercept form is given by y=mx+b, where m is the slope and b is the y-intercept.

Step 2 ：We know the slope m is 1, and we know that the line passes through the point (5,8). We can substitute these values into the equation to solve for b.

Step 3 ：Substituting m=1 and (x,y)=(5,8) into the equation y=mx+b, we get 8=5+b.

Step 4 ：Solving for b, we find that b=3.

Step 5 ：Substituting m=1 and b=3 back into the equation y=mx+b, we get the equation of the line: y=x+3.

Step 6 ：y=x+3 is the equation of the line that passes through the point (5,8) and has a slope of 1.

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