1. Given $f (x) = x^{2} + 3 x - 7$ , evaluate $f (2)$ . 0
2. State the domain and range for the given function.2
Domain:
Range:
3. Write the equation for a parabola that is vertically stretched by a factor of 3 , reflected in the $x$ -axis and translated right 2 units.
4. State whether each of the following represents a linear, quadratic or exponential function.2
a) $y = 2 x - 1$
b) $y = (1 / 2)^{x}$
PART C: FULL SOLUTIONS REOUIRED[21 Marks]
1. Expand and simplify. $(3 y - 2) (y + 1) - 2 (y - 4) 3$
2. Factor each expression.
a) $9 x^{2} - 81$
b) $- 8 x^{2} + 44 x - 48$
3. Solve by factoring or using the quadratic formula
a) $x^{2} - 5 x + 6 = 02$
b) $2 x^{2} + 3 x - 1 = 0$
MCF3M1 Culminating Task June 2023
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Answer

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Answer

4b) $y = (\frac{1}{2})^{x}$ is a $exponential$ function.

Steps

Step 1 ： $f (2) = (2)^{2} + 3 (2) - 7 = 4 + 6 - 7 = 3$

Step 2 ：Domain: $(- \infty, \infty)$

Step 3 ：Range: $(- \infty, \infty)$

Step 4 ：3. $y = - 3 (x - 2)^{2} = - 3 (x^{2} - 4 x + 4)$

Step 5 ：4a) $y = 2 x - 1$ is a $linear$ function.

Step 6 ：4b) $y = (\frac{1}{2})^{x}$ is a $exponential$ function.