Write the equilibrium expression, Kb, for the reaction represented above.
Kb=0
Step 1 :Kb=[B]2[A]2
Step 2 :Kb=(b+5)2(2b−3)2
Step 3 :Kb=(−5+5)2(2(−5)−3)2
Step 4 :Kb=02(−13)2
Step 5 :Kb=0169
Step 6 :Kb=0