6a) Plot the following points: $A (8, - 2), B (8, 4)$ , $C (- 1, 4)$
6b) Perform a scale factor of $1 / 3$ , keeping $C$ in the same place. Dilatation $\to B^{'} = (,)$

Answer

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Answer

\boxed{B' = (2, 4)}

Steps

Step 1 ：Find the vector from point C to point B: $\vec{C B} = (8 - (- 1), 4 - 4) = (9, 0)$

Step 2 ：Multiply the vector by the scale factor: $\vec{C B^{'}} = \frac{1}{3} \vec{C B} = (3, 0)$

Step 3 ：Add the scaled vector to point C: $B^{'} = C + \vec{C B^{'}} = (- 1 + 3, 4 + 0) = (2, 4)$

Step 4 ：\boxed{B' = (2, 4)}