(a) x^{2}-5 x+2=0

Question

(a) x^{2}-5 x+2=0

Accepted Answer

Step:1 ：Given the quadratic equation: (x^2 - 5x + 2 = 0)Step:2 ：Using the quadratic formula: (x = frac{-b pm sqrt{b^2 - 4ac}}{2a}), where (a = 1), (b = -5), and (c = 2)Step:3 ：Calculate the discriminant: (Delta = b^2 - 4ac = (-5)^2 - 4(1)(2) = 17)Step:4 ：Find the roots: (x_1 = frac{-(-5) + sqrt{17}}{2(1)} approx 4.7913) and (x_2 = frac{-(-5) - sqrt{17}}{2(1)} approx 0.2087)Step:5 ：(boxed{x_1 approx 4.7913, x_2 approx 0.2087})

Answer

Step: 1 ：Given the quadratic equation: (x^2 - 5x + 2 = 0)Step: 2 ：Using the quadratic formula: (x = frac{-b pm sqrt{b^2 - 4ac}}{2a}), where (a = 1), (b = -5), and (c = 2)Step: 3 ：Calculate the discriminant: (Delta = b^2 - 4ac = (-5)^2 - 4(1)(2) = 17)Step: 4 ：Find the roots: (x_1 = frac{-(-5) + sqrt{17}}{2(1)} approx 4.7913) and (x_2 = frac{-(-5) - sqrt{17}}{2(1)} approx 0.2087)Step: 5 ：(boxed{x_1 approx 4.7913, x_2 approx 0.2087})

(a) $x^{2}-5 x+2=0$

Answer

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