Problem

15-5 어떤 단세포 생물의 집단은 1 분마다 $30 \%$ 가 죽고, 나머지는 각각 두 마리로 분열한다고 한다. 처음 10 마리의 단세포 생물의 수가 처음으로 1000 마리 이상이 되는 것은 몇 분 후인가? 단, $1.4^{13}=79.4$ 로 계산한다.

Answer

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Answer

\( \boxed{14} \) minutes are needed for the population of single-celled organisms to reach 1000 or more.

Steps

Step 1 :Given the initial population P(0) = 10, and the growth rule P(t+1) = 2 * (1 - 0.3) * P(t), we need to find the smallest integer t such that P(t) >= 1000.

Step 2 :Using the given value of $1.4^{13} = 79.4$, we can calculate the population at time t as P(t) = 10 * $1.4^t$.

Step 3 :We need to find the smallest integer t such that 10 * $1.4^t$ >= 1000.

Step 4 :By trial and error, we find that t = 14 gives a population of 10 * $1.4^{14}$ = 1111.2, which is greater than 1000.

Step 5 :\( \boxed{14} \) minutes are needed for the population of single-celled organisms to reach 1000 or more.

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