x^{2}-3 x-5=0

Question

x^{2}-3 x-5=0

Accepted Answer

Step:1 ：Given the quadratic equation (x^2 - 3x - 5 = 0), we can use the quadratic formula to find the roots: (x = frac{-b pm sqrt{b^2 - 4ac}}{2a}), where (a = 1), (b = -3), and (c = -5).Step:2 ：Calculate the discriminant: (Delta = b^2 - 4ac = (-3)^2 - 4(1)(-5) = 9 + 20 = 29).Step:3 ：Find the roots: (x_1 = frac{-(-3) + sqrt{29}}{2(1)} approx 4.19) and (x_2 = frac{-(-3) - sqrt{29}}{2(1)} approx -1.19).Step:4 ：(boxed{text{Final Answer: The roots of the quadratic equation } x^2 - 3x - 5 = 0 text{ are approximately } 4.19 text{ and } -1.19})

Answer

Step: 1 ：Given the quadratic equation (x^2 - 3x - 5 = 0), we can use the quadratic formula to find the roots: (x = frac{-b pm sqrt{b^2 - 4ac}}{2a}), where (a = 1), (b = -3), and (c = -5).Step: 2 ：Calculate the discriminant: (Delta = b^2 - 4ac = (-3)^2 - 4(1)(-5) = 9 + 20 = 29).Step: 3 ：Find the roots: (x_1 = frac{-(-3) + sqrt{29}}{2(1)} approx 4.19) and (x_2 = frac{-(-3) - sqrt{29}}{2(1)} approx -1.19).Step: 4 ：(boxed{text{Final Answer: The roots of the quadratic equation } x^2 - 3x - 5 = 0 text{ are approximately } 4.19 text{ and } -1.19})

$x^{2}-3 x-5=0$

Answer

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