Problem

\( \begin{array}{l}+\square=8 \\ +\quad++=6 \\ \begin{array}{cl}11 & \text { II } \\ 13 & 8\end{array} \\\end{array} \)

Answer

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Answer

\( \begin{array}{cl}11-x & \text { II } \\ 13-x & 8\end{array} \)

Steps

Step 1 ：\( x = 8 - \square \)

Step 2 ：\( 6 - x = \quad \)

Step 3 ：\( \begin{array}{cl}11-x & \text { II } \\ 13-x & 8\end{array} \)

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