Write the equation of the line that is perpendicular to y=-2 x+1 and passes through (4,-2)

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Accepted Answer

Step:1 ：The slope of the given line is -2.Step:2 ：The slope of a line perpendicular to this line would be the negative reciprocal of -2, which is 1/2.Step:3 ：The equation of a line is given by (y = mx + c), where m is the slope and c is the y-intercept.Step:4 ：We know the slope (m) and a point on the line (4,-2), so we can substitute these values into the equation to find the y-intercept (c).Step:5 ：After substituting, we get m = 0.5 and c = -4.0.Step:6 ：(boxed{y = frac{1}{2}x - 4}) is the equation of the line.

Answer

Step: 1 ：The slope of the given line is -2.Step: 2 ：The slope of a line perpendicular to this line would be the negative reciprocal of -2, which is 1/2.Step: 3 ：The equation of a line is given by (y = mx + c), where m is the slope and c is the y-intercept.Step: 4 ：We know the slope (m) and a point on the line (4,-2), so we can substitute these values into the equation to find the y-intercept (c).Step: 5 ：After substituting, we get m = 0.5 and c = -4.0.Step: 6 ：(boxed{y = frac{1}{2}x - 4}) is the equation of the line.

Write the equation of the line that is perpendicular to $y=-2 x+1$ and passes through $(4,-2)$

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