Find the area of the region bounded by the graphs of the given equations.
\[
y=x, y=\sqrt[8]{x}
\]
Set up the integral(s) that will give the area of the region. Select the correct choice below and fill in any answer box(es) to complete the choice.
$\int_{\square}^{2}[\square] d x$
B.
The area is
(Type an integer or a simplified fraction.)

Step 1 ：The area between two curves is given by the integral of the absolute difference between the functions defining the curves. In this case, the functions are \(y=x\) and \(y=x^{1/8}\).

Step 2 ：We need to find the intersection points of these two curves to determine the limits of integration. The intersection points are the solutions to the equation \(x = x^{1/8}\).

Step 3 ：The intersection points are \(x=0\) and \(x=1\). These will be the limits of our integral.

Step 4 ：The integrand will be the absolute difference between the two functions, which is \(|x - x^{1/8}|\). However, since \(x\) is always greater than or equal to \(x^{1/8}\) in the interval [0,1], we can simplify the integrand to \(x - x^{1/8}\).

Step 5 ：Setting up the integral to find the area, we get \(\int_{0}^{1}(x - x^{1/8}) dx\).

Step 6 ：Calculating the integral, we find that the area is \(\boxed{\frac{7}{8}}\).