Write the following as a sum of logarithms:
\[
\ln \left(\frac{e^{3} x^{4}}{y^{5}}\right)=\square+\square \ln (x)+\square \ln (y)
\]
Final Answer: \(\ln \left(\frac{e^{3} x^{4}}{y^{5}}\right) = \boxed{3 + 4\ln(x) - 5\ln(y)}\)
Step 1 :Write the following as a sum of logarithms: \(\ln \left(\frac{e^{3} x^{4}}{y^{5}}\right)=\square+\square \ln (x)+\square \ln (y)\)
Step 2 :The question is asking to express the given logarithmic expression as a sum of logarithms. The properties of logarithms can be used to simplify the expression. The properties of logarithms that will be used are:
Step 3 :1. The logarithm of a quotient is the difference of the logarithms: \(\ln(a/b) = \ln(a) - \ln(b)\)
Step 4 :2. The logarithm of a product is the sum of the logarithms: \(\ln(ab) = \ln(a) + \ln(b)\)
Step 5 :3. The logarithm of a power is the product of the logarithm and the exponent: \(\ln(a^n) = n\ln(a)\)
Step 6 :Using these properties, the given expression can be simplified as follows: \(\ln \left(\frac{e^{3} x^{4}}{y^{5}}\right) = \ln(e^3) + \ln(x^4) - \ln(y^5)\)
Step 7 :Then, applying the third property of logarithms: \(\ln(e^3) + \ln(x^4) - \ln(y^5) = 3\ln(e) + 4\ln(x) - 5\ln(y)\)
Step 8 :Since the natural logarithm of e is 1, the final expression is: \(3\ln(e) + 4\ln(x) - 5\ln(y) = 3 + 4\ln(x) - 5\ln(y)\)
Step 9 :Final Answer: \(\ln \left(\frac{e^{3} x^{4}}{y^{5}}\right) = \boxed{3 + 4\ln(x) - 5\ln(y)}\)