Problem

Write the following as a sum of logarithms:
ln(e3x4y5)=+ln(x)+ln(y)

Answer

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Answer

Final Answer: ln(e3x4y5)=3+4ln(x)5ln(y)

Steps

Step 1 :Write the following as a sum of logarithms: ln(e3x4y5)=+ln(x)+ln(y)

Step 2 :The question is asking to express the given logarithmic expression as a sum of logarithms. The properties of logarithms can be used to simplify the expression. The properties of logarithms that will be used are:

Step 3 :1. The logarithm of a quotient is the difference of the logarithms: ln(a/b)=ln(a)ln(b)

Step 4 :2. The logarithm of a product is the sum of the logarithms: ln(ab)=ln(a)+ln(b)

Step 5 :3. The logarithm of a power is the product of the logarithm and the exponent: ln(an)=nln(a)

Step 6 :Using these properties, the given expression can be simplified as follows: ln(e3x4y5)=ln(e3)+ln(x4)ln(y5)

Step 7 :Then, applying the third property of logarithms: ln(e3)+ln(x4)ln(y5)=3ln(e)+4ln(x)5ln(y)

Step 8 :Since the natural logarithm of e is 1, the final expression is: 3ln(e)+4ln(x)5ln(y)=3+4ln(x)5ln(y)

Step 9 :Final Answer: ln(e3x4y5)=3+4ln(x)5ln(y)

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