$2 x^{2}-5 x+3$
Final Answer: The roots of the equation \(2 x^{2}-5 x+3\) are \(\boxed{1.5}\) and \(\boxed{1.0}\).
Step 1 :This is a quadratic equation of the form \(ax^2 + bx + c\).
Step 2 :The roots of this equation can be found using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
Step 3 :Given that a = 2, b = -5, and c = 3.
Step 4 :Calculate the discriminant (D) using the formula \(D = b^2 - 4ac\). In this case, D = 1.
Step 5 :Substitute the values of a, b, and D into the quadratic formula to find the roots of the equation.
Step 6 :The roots of the equation are x1 = 1.5 and x2 = 1.0.
Step 7 :Final Answer: The roots of the equation \(2 x^{2}-5 x+3\) are \(\boxed{1.5}\) and \(\boxed{1.0}\).