For the function $f(x)=4 x+2$, find $f^{-1}(x)$.
\(\boxed{f^{-1}(x) = \frac{x - 2}{4}}\)
Step 1 :Switch the roles of x and y: \(x = 4y + 2\)
Step 2 :Solve for y: \(y = \frac{x - 2}{4}\)
Step 3 :\(\boxed{f^{-1}(x) = \frac{x - 2}{4}}\)