Problem

For the function $f (x) = 4 x + 2$ , find $f^{- 1} (x)$ .

Answer

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Answer

$f^{- 1} (x) = \frac{x - 2}{4}$

Steps

Step 1 ：Switch the roles of x and y: $x = 4 y + 2$

Step 2 ：Solve for y: $y = \frac{x - 2}{4}$

Step 3 ： $f^{- 1} (x) = \frac{x - 2}{4}$

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