For the function $f(x)=\sqrt[3]{x}+4$, find $f^{-1}(x)$.
Final Answer: \(\boxed{f^{-1}(x) = (x - 4)^3}\)
Step 1 :Given function: \(y = \sqrt[3]{x} + 4\)
Step 2 :Swap x and y: \(x = \sqrt[3]{y} + 4\)
Step 3 :Solve for y: \(y = (x - 4)^3\)
Step 4 :Final Answer: \(\boxed{f^{-1}(x) = (x - 4)^3}\)