A metallurgist has one alloy containing $49 \%$ copper and another containing $62 \%$ copper. How many pounds of each alloy must he use to make 51 pounds of a third alloy containing $56 \%$ copper? (Round to two decimal places if necessary.)

Step 1 ：Let's denote the amount of the first alloy (49% copper) as x and the amount of the second alloy (62% copper) as y.

Step 2 ：We know that the total amount of the two alloys is 51 pounds, so we have the equation \(x + y = 51\).

Step 3 ：We also know that the total amount of copper in the two alloys is 56% of 51 pounds, so we have the equation \(0.49x + 0.62y = 0.56 * 51\).

Step 4 ：We can solve this system of equations to find the values of x and y.

Step 5 ：Final Answer: The metallurgist must use \(\boxed{x}\) pounds of the first alloy and \(\boxed{y}\) pounds of the second alloy to make 51 pounds of a third alloy containing 56% copper.