Find the equation of a line described as follows, and express your answer in point-slope form, slopeintercept form, and standard form.
Find the equation of the line parallel to the line $3 x-2 y=9$
that passes through the point $(1,-2)$

Step 1 ：The slope of a line given by the equation \(ax + by = c\) is \(-a/b\). So, the slope of the line \(3x - 2y = 9\) is \(-3/2\). A line parallel to this line will have the same slope. So, the slope of the line we are looking for is also \(-3/2\).

Step 2 ：The point-slope form of a line is \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is a point on the line and \(m\) is the slope of the line. We can substitute the given point \((1, -2)\) and the slope \(-3/2\) into this equation to find the equation of the line in point-slope form.

Step 3 ：The slope-intercept form of a line is \(y = mx + b\), where \(m\) is the slope of the line and \(b\) is the y-intercept. We can rearrange the point-slope form of the line to find the slope-intercept form.

Step 4 ：The standard form of a line is \(Ax + By = C\), where \(A\), \(B\), and \(C\) are integers, and \(A\) and \(B\) are not both zero. We can rearrange the slope-intercept form of the line to find the standard form.

Step 5 ：Final Answer: The equation of the line in point-slope form is \(\boxed{y + 2 = -\frac{3}{2}(x - 1)}\), in slope-intercept form is \(\boxed{y = -\frac{3}{2}x - 1}\), and in standard form is \(\boxed{3x + 2y = -1}\).