Graph the line that contains the point $(-4,-6)$ and has a slope of $\frac{2}{3}$

Step 1 ：We are given a point (-4,-6) and a slope of $\frac{2}{3}$.

Step 2 ：We can use the slope-intercept form of a line, which is $y=mx+b$, where $m$ is the slope and $b$ is the y-intercept.

Step 3 ：We substitute the given point and slope into the equation to solve for $b$.

Step 4 ：Substituting $m=\frac{2}{3}$ and the point (-4,-6) into the equation, we get $-6=\frac{2}{3}\ast (-4)+b$.

Step 5 ：Solving for $b$, we get $b=-\frac{10}{3}$.

Step 6 ：Thus, the equation of the line is $y=\frac{2}{3}x-\frac{10}{3}$.

Step 7 ：To graph this line, we plot the y-intercept at $-\frac{10}{3}$ on the y-axis.

Step 8 ：From this point, we rise 2 units and run 3 units to plot the next point due to the slope of $\frac{2}{3}$.

Step 9 ：We continue this pattern to complete the graph of the line.

Step 10 ：$\boxed{{\displaystyle y=\frac{2}{3}x-\frac{10}{3}}}$ is the final answer.