Graph the line that contains the point $(-4,-6)$ and has a slope of $\frac{2}{3}$

Step 1 ：We are given a point (-4,-6) and a slope of \(\frac{2}{3}\).

Step 2 ：We can use the slope-intercept form of a line, which is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.

Step 3 ：We substitute the given point and slope into the equation to solve for \(b\).

Step 4 ：Substituting \(m = \frac{2}{3}\) and the point (-4,-6) into the equation, we get \(-6 = \frac{2}{3}*(-4) + b\).

Step 5 ：Solving for \(b\), we get \(b = -\frac{10}{3}\).

Step 6 ：Thus, the equation of the line is \(y = \frac{2}{3}x - \frac{10}{3}\).

Step 7 ：To graph this line, we plot the y-intercept at \(-\frac{10}{3}\) on the y-axis.

Step 8 ：From this point, we rise 2 units and run 3 units to plot the next point due to the slope of \(\frac{2}{3}\).

Step 9 ：We continue this pattern to complete the graph of the line.

Step 10 ：\(\boxed{y = \frac{2}{3}x - \frac{10}{3}}\) is the final answer.