Complete the equation of the line through $(-8,8)$ and $(1,-10)$. Use exact numbers.

Step 1 ：Given two points (-8,8) and (1,-10), we need to find the equation of the line passing through these points.

Step 2 ：The equation of a line in slope-intercept form is given by \(y = mx + b\), where \(m\) is the slope of the line and \(b\) is the y-intercept.

Step 3 ：The slope of the line passing through two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by \(m = \frac{y_2 - y_1}{x_2 - x_1}\).

Step 4 ：Substituting the given points into the slope formula, we find that \(m = -2.0\).

Step 5 ：Once we have the slope, we can substitute one of the points and the slope into the equation to solve for \(b\). Doing this, we find that \(b = -8.0\).

Step 6 ：Substituting \(m\) and \(b\) into the equation of the line, we get the final equation of the line: \(y = -2x - 8\).

Step 7 ：\(\boxed{y = -2x - 8}\) is the final answer.