Given that $f(x)=2 x+3$ and $g(x)=x^{2}-3 x-4$, find $(g \circ f)(7)$
$(g \circ f)(7)=$
(Simplify your answer.)

Answer

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Answer

Therefore, the value of $(g \circ f)(7)$ is $\boxed{234}$.

Steps

Step 1 ：Given that $f(x)=2 x+3$ and $g(x)=x^{2}-3 x-4$, we need to find $(g \circ f)(7)$.

Step 2 ：First, we find the value of $f(7)$. Substituting $x = 7$ into $f(x)$, we get $f(7) = 17$.

Step 3 ：Next, we substitute this value into $g(x)$ to find $g(f(7))$. Substituting $x = 17$ into $g(x)$, we get $g(f(7)) = 234$.

Step 4 ：Therefore, the value of $(g \circ f)(7)$ is $\boxed{234}$.