The functions $f$ and $g$ are such that
\[
\begin{array}{l}
f(x)=\frac{1}{2} x+3 \\
g(x)=\frac{14}{2 x-3}
\end{array}
\]
What number cannot be included in the domain of $g$ ?

Answer

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Answer

$\boxed{\frac{3}{2}}$ cannot be included in the domain of $g(x)$

Steps

Step 1 ：Given the functions $f(x) = \frac{1}{2}x + 3$ and $g(x) = \frac{14}{2x - 3}$

Step 2 ：To find the number that cannot be included in the domain of $g(x)$, we need to find the value of x that makes the denominator of the fraction equal to zero.

Step 3 ：Set the denominator equal to zero: $2x - 3 = 0$

Step 4 ：Solve for x: $x = \frac{3}{2}$

Step 5 ：$\boxed{\frac{3}{2}}$ cannot be included in the domain of $g(x)$

The functions $f$ and $g$ are such that\[\begin{array}{l}f(x)=\frac{1}{2} x+3 \\g(x)=\frac{14}{2 x-3}\end{array}\]What number cannot be included in the domain of $g$ ?

Answer

Popular Problems

The functions $f$ and $g$ are such that
\[
\begin{array}{l}
f(x)=\frac{1}{2} x+3 \\
g(x)=\frac{14}{2 x-3}
\end{array}
\]
What number cannot be included in the domain of $g$ ?